-36x-4x^2=0

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Solution for -36x-4x^2=0 equation: 



-36x-4x^2=0

a = -4; b = -36; c = 0;
Δ = b2-4ac
Δ = -362-4·(-4)·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-36}{2*-4}=\frac{0}{-8}
=0
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+36}{2*-4}=\frac{72}{-8}
=-9
$

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